Can skuid.snippet.registerSnippet() handle multiple snippets?

No, but it’s a good idea. You could implement this yourself with a little code:

var snippets = {
   ‘snippetName1’: function() { … },
   ‘snippetName2’: function() { … }
};

skuid.$.each(snippets,function(name,func){ skuid.snippet.registerSnippet(name,func); });

nice!