In UI formula fields on any model, I am unable to check if the reference field is blank or not. The following does not work -
IF( {{refrence__c}} != null, ‘Not Null’, ‘Is Null’)
tried this link but does not help - https://community.skuid.com/t/how-can-you-check-for-null-and-or-if-the-field-exists-in-a-…
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Try to change the formula to:
IF({{refrence__c}}, 'Not Null', 'Is Null')
I have already tried that and it dint work 
Okai, I’m unable to reproduce that. A few questions for you:
- What return type did you specify on your field?
- Did you check the spelling of your reference field inside the formula?
- Which version of Skuid are you working on?
Return type is a string only and yes the reference field value is correct. This is what I am trying to do -
IF( {{Parent__c}} , 'Parent : ’ + {{Name}}, 'Child : ’ + {{Name}} )
Skuid version is 8.15.4
Can you try to update to the latest version? I copied your formula and it is working fine for me.
It works with the latest version. However it was not working in 8.15.4
Thanks 
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