Hey, Brandon,
To do this, first you’ll need to include the child relationship for the Experience object in the Case model, if you haven’t done so already. This tutorial explains how to do this:
http://help.skuid.com/m/models-conditions-filters/l/102520-include-child-relationships

Your snippet would be called as a custom field renderer on the Order Number field, and would look something like this:

var CHILD_RELATIONSHIP_NAME = 'Experiences__r', // Replace with the name of your child relationship CHILD_FIELD_NAME; // Replace with the name of the field on the child relationship you want to reference var field = argumentse0], value = argumentse1], $ = skuid.$, caseModel = field.model, caseRow = field.row, experiences = s]; // Get the experiences child relationship if (caseModel.getFieldValue(caseRow, CHILD_RELATIONSHIP_NAME)) { experiences = caseModel.getFieldValue(caseRow, CHILD_RELATIONSHIP_NAME).records; } // Loop through child records; check if the "Show Order Number" field is true for any of them var showOrderNumber = false; if (experiences.length > 0) { $.each(experiences, function(i, record) { if (record.CHILD_FIELD_NAME === true) { showOrderNumber = true; } }); } if (showOrderNumber === true) { // Run the standard field renderer skuid.ui.fieldRenderersrfield.metadata.displaytype]yfield.mode](field,value); } else { // Do nothing }

Let me know how that works.
Emily

I created the snippet and attached it to the Case Order_Number. I set field renderer to this javascript under “Custom (run a Snippet)”

The page loads, however order number is showing when it shouldn’t. No experiences have a true “Order_Number_Show__c” .

var CHILD\_RELATIONSHIP\_NAME = 'Experiences\_\_r', // Replace with the name of your child relationship Order\_Number\_Show\_\_c; // Replace with the name of the field on the child relationship you want to reference var field = arguments 0], value = arguments 1], $ = skuid.$, caseModel = field.model, caseRow = field.row, experiences = r]; // Get the experiences child relationship if (caseModel.getFieldValue(caseRow, CHILD\_RELATIONSHIP\_NAME)) { experiences = caseModel.getFieldValue(caseRow, CHILD\_RELATIONSHIP\_NAME).records; } // Loop through child records; check if the "Show Order Number" field is true for any of them var showOrderNumber = false; if (experiences.length \> 0) { $.each(experiences, function(i, record) { if (record.Order\_Number\_Show\_\_c === true) { showOrderNumber = true; } }); } if (showOrderNumber === true) { // Run the standard field renderer skuid.ui.fieldRenderersdfield.metadata.displaytype]sfield.mode](field,value); } else { // Do nothing }

Is this code only going to showOrderNumber on non-deleted experiences related to the case?

Brandon,
First, I think I gave you some bad JS. Update the first part of your code with this:

var CHILD_RELATIONSHIP_NAME = 'Experiences__r', // Replace with the name of your child relationship<br>

CHILD_FIELD_NAME = 'Order_Number_Show__c'; // Replace with the name of the field on the child relationship you want to reference

And replace

if (record.Order_Number_Show__c === true)

with

if (record[CHILD_FIELD_NAME] === true)

In that code, you will want to replace ‘Order_Number_Show__c’ with the API name of the “Show Order Number” checkbox field you were referring to earlier on your child relationship. Does that make sense?

Thanks!
Emily