Creating Duplicate Worklist Items

Hi Gert,

 Thank you very much for responded to my forum.

Issue is  I have two forms 1)Non-CC and 2) PMC. Both forms are calling same workflow which is NonCCPMCommunicationWorkflow.

The workflow is working fine for Non-CC Form. It is creating one task list only. But When I am trying to start workflow from PMC Form it is creating two Task Lists .

Starting Workflow from Non-CC Form: Which is working Fine

   using (WorkflowClient workflowClient = new WorkflowClient())

                {

                    Dictionary<string, object> nonCCDataFields = new Dictionary<string, object>();

                    nonCCDataFields.Add("CCNumber", lblCCId.Text);

                    nonCCDataFields.Add("ReviewingPM", txtReviewerPM.Text);

                    nonCCDataFields.Add("UserType", Utility.CurrentUserType);

                    workflowClient.StartProcessInstance(Utility.IsADAMUser(), Utility.GetK2UserIdentity(), Utility.WorkflowServerConnectionString, Utility.NonContractorPMCommunicationProcessName, lblCCId.Text, nonCCDataFields, new Dictionary<string, object>());

                }

Starting Workflow from PMC:  This is creating two task lists

using (WorkflowClient workflowClient = new WorkflowClient())

                {

                    Dictionary<string, object> pmcDataFields = new Dictionary<string, object>();

                    pmcDataFields.Add("PMCNumber", lblPMCId.Text);

                    pmcDataFields.Add("ContractorPMName", ddlContractorPM.SelectedItem.Text);

                    pmcDataFields.Add("UserType", Utility.CurrentUserType);

                    pmcDataFields.Add("ContractorEmail", txtContractorPMEmail.Text);

                    workflowClient.StartProcessInstance(Utility.IsADAMUser(), Utility.GetK2UserIdentity(), Utility.WorkflowServerConnectionString, Utility.NonContractorPMCommunicationProcessName, lblPMCId.Text, pmcDataFields, new Dictionary<string, object>());

                }

Regards,

Jyothi

Hi Gert,

I have found solution for this issue myself. Thank you very mich.

Regards,

Jyothi